The Dark Side of Will wrote:Because of their use in series and their different efficiencies, using a turbo and a roots does NOT involve any synergy. In order for a combination of two effects to be greater than their sum, the combination must involve a net INCREASE in efficiency. This does not happen....
What efficiencies are you referring too? volumetric or thermal? I just need some clarification?!?...and for the term "synergy" for the sake of not sounding like a broken record...I will respectfully agree to disagree...so we can move forward :thumbleft:
my point was and is simply, twincharging in this context takes the disadvantages of both units applied singularly and removes or minimizes them when combined...
Will cont'd wrote:...The blower takes whatever comes into its maw and tries to push that through at a certain volume rate. Because the engine is pulling air at a lower volume rate, boost results, increasing the mass flow at a given volume flow. The blower doesn't care if it's inlet pressure is 4 psi or 40. It'll take more power to drive at 40, but that's because it's compressing a greater mass flow of air (and adding a lot of heat due to its low efficiency)1. Like all volumetric systems (such as a piston engine), the equations describing blower operation are based on pressure *difference*, while the equations describing the operation of a non-volumetric system like a turbo are based on pressure *ratio*. Trying to apply pressure ratio based ideas to a roots blower doesn't give correct results 2...
1 Of course the blower "wants to become an engine" when you are force feeding it...but it still only adds its contribution of pressure to the already higher density air. The mass of air does not matter to the blower...when do you reach a point of diminishing returns I simply don't have numbers to back it up nor do you to say otherwise. Of course conceptually it may seem one way...
This is an example of someone using an M90/turbo on a small displacement engine and is able to get 30Xhp to the wheels @ 9psi. This is ONLY an example regarding numbers...nothing more.
http://www.calaisturbo.com.au/showthread.php?t=90589
2You are absolutely right, no argument there but on an earlier post I tried to differentiate psia from psig...it is too boring to do conversions when I am discussing with someone who can also intellectualize the issue...you know what I meant...
Will cont'd wrote:Volumetric pumps are inefficient by virtue of their design...but one will be mistaken if suggesting this units are simply inefficient on all counts...not the case as according to Eaton/Mag efficiency can reach up to .9; this is of course very dependent on the dynamic state of engines Ve and speed the unit will be ran at...
Efficiency of a roots or Eaton might be .9 at next to no boost, but it drops like a stone as boost (pressure difference) goes up.
No argument there either, I actually mistyped that I meant to say .6 ...root blowers have a wider operating range and a higher AVERAGE efficiency...again from the fact that they don't compress air internally, but we are given it a headstart...
Will cont'd wrote:...If there's something wrong with my math or my example, find it and explain why. Continuing to disagree without an explanation or acknowledgment/evaluation of the correctness of the example just strikes me as illogical...
Forget the Math, it does not apply and goes beyond the scope of the board...a positive displacement compressor with an isovolumetric process eg a Roots-type blower;
The problem here is the primary stage delivers the air compressed at said pressure, thereby providing said volume. This volume will be the intake of the secondary stage. The secondary stage can match the volume and does not compress the air any more than what is statically does...in any event here is the Characteristic data :
www.eng-tips.com
Q1 = External displaced volume at p1/ time
Qv = internal leakage-losses at dp/time
Qv100 = internal leakage-losses at a dp of 100 millibar/time
q0 = internal displaced volume per rotation
p1 = pressure at inlet
p2 = pressure at outlet
n = number of rotation/minute...
...plus who has hard numbers?
What the formula shows is that each manufacturer and type of blower will have a specific value for internal leakage and not solemnly based on pressure differential...I don't have numbers but it stands to reason given all generations of say the M90as an example their respective internal leakage IS NOT THE SAME, they do all leak but at a certain rate. Again if you are saying the more boost hence more leakage...then you will be right, if we are dealing with ambient conditions; where pulley size dictates the amount of pressure and speed. In this context I have stipulated we go no more than 2 bars. If I do not overdrive the blower and push say 10psig from the turbo...then how does this translate to blower inefficiency...remember we are discussing contextually!!